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Hypothèses
- BC || DF;
- Certaines mesures sont données.
Question
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Affirmations |
Justifications |
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\( \angle BCA \cong \angle FDE \)
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\( \frac{m\overline{DE}}{m\overline{CA}} = \frac{m\overline{DF}}{m\overline{CB}} \Rightarrow \frac{10}{4} = \frac{15}{6} = 2,5\)
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\( \Delta ABC \sim \Delta EFD \)
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\( \frac{m\overline{EF}}{m\overline{AB}} = 2,5 \to \frac{14}{m\overline{AB}} = 2,5 \to m\overline{AB} = 5,6\: cm \)
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