{"id":983,"date":"2016-01-13T13:15:51","date_gmt":"2016-01-13T18:15:51","guid":{"rendered":"http:\/\/pascal-tic.org\/math\/?page_id=983"},"modified":"2019-08-27T11:47:10","modified_gmt":"2019-08-27T16:47:10","slug":"aire-dun-quadrilatere","status":"publish","type":"page","link":"https:\/\/pascal-tic.org\/math\/aire-dun-quadrilatere\/","title":{"rendered":"Aire d&rsquo;un quadrilat\u00e8re"},"content":{"rendered":"<section class=\"l-section wpb_row height_medium\"><div class=\"l-section-h i-cf\"><div class=\"g-cols vc_row via_flex valign_top type_default\"><div class=\"vc_col-sm-6 wpb_column vc_column_container\"><div class=\"vc_column-inner\"><div class=\"wpb_wrapper\"><div class=\"w-image align_none us_animate_afl\"><div class=\"w-image-h\"><img loading=\"lazy\" decoding=\"async\" width=\"912\" height=\"755\" src=\"https:\/\/pascal-tic.org\/math\/wp-content\/uploads\/2016\/01\/AireTrapezeCST4-5.png\" class=\"attachment-full size-full\" alt=\"\" srcset=\"https:\/\/pascal-tic.org\/math\/wp-content\/uploads\/2016\/01\/AireTrapezeCST4-5.png 912w, https:\/\/pascal-tic.org\/math\/wp-content\/uploads\/2016\/01\/AireTrapezeCST4-5-300x248.png 300w, https:\/\/pascal-tic.org\/math\/wp-content\/uploads\/2016\/01\/AireTrapezeCST4-5-768x636.png 768w, https:\/\/pascal-tic.org\/math\/wp-content\/uploads\/2016\/01\/AireTrapezeCST4-5-600x497.png 600w\" sizes=\"auto, (max-width: 912px) 100vw, 912px\" \/><\/div><\/div><\/div><\/div><\/div><div class=\"vc_col-sm-6 wpb_column vc_column_container\"><div class=\"vc_column-inner\"><div class=\"wpb_wrapper\"><div class=\"wpb_text_column\"><div class=\"wpb_wrapper\"><h4>Apr\u00e8s avoir d\u00e9montr\u00e9 que ce quadrilat\u00e8re est un trap\u00e8ze, d\u00e9termine son aire.<\/h4>\n<\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/section><section class=\"l-section wpb_row height_medium\"><div class=\"l-section-h i-cf\"><div class=\"g-cols vc_row via_flex valign_top type_default\"><div class=\"vc_col-sm-12 wpb_column vc_column_container\"><div class=\"vc_column-inner\"><div class=\"wpb_wrapper\"><div class=\"w-tabs style_default switch_click accordion type_togglable has_scrolling\" style=\"--sections-title-size:inherit\"><div class=\"w-tabs-sections titles-align_none icon_chevron cpos_right\"><div class=\"w-tabs-section\" id=\"o980\"><button aria-controls=\"content-o980\" class=\"w-tabs-section-header with_icon\"><i class=\"fas fa-puzzle-piece\"><\/i><div class=\"w-tabs-section-title\">Solution<\/div><div class=\"w-tabs-section-control\"><\/div><\/button><div  class=\"w-tabs-section-content\" id=\"content-o980\" aria-expanded=\"false\"><div class=\"w-tabs-section-content-h i-cf\"><div class=\"wpb_text_column\"><div class=\"wpb_wrapper\"><p><strong>1. Pente de JK<\/strong><\/p>\n<p>3\/4<\/p>\n<p><strong>2. Pente de GH<\/strong><\/p>\n<p>3\/4<\/p>\n<p><em>Le quadrilat\u00e8re est un trap\u00e8ze!<\/em><\/p>\n<p><strong>3. R\u00e8gle de la droite JK<\/strong><\/p>\n<p>y = 3\/4 x + 1,5<\/p>\n<p><strong>4. Pente de la droite perpendiculaire \u00e0 JK passant par G<\/strong><\/p>\n<p>-4\/3<\/p>\n<p><strong>5. R\u00e8gle de la droite GC (la hauteur)<\/strong><\/p>\n<p>y = -4\/3 x + 39<\/p>\n<p><strong>6. Coordonn\u00e9es du point C (Intersection entre JK et GC)<\/strong><\/p>\n<p>(18,15)<\/p>\n<p><strong>7. Distance entre GC (la hauteur)<\/strong><\/p>\n<p>20 u<\/p>\n<p><strong>8. Distance entre GH (la petite base)<\/strong><\/p>\n<p>15 u<\/p>\n<p><strong>9. Distance entre JK (la grande base)<\/strong><\/p>\n<p>50 u<\/p>\n<p><strong>10. Aire du trap\u00e8ze<\/strong><\/p>\n<p>650 u\u00b2<\/p>\n<p><em>Attention, ce trap\u00e8ze n&rsquo;est pas isoc\u00e8le&#8230; GJ = 25 u et HK = 28,28 u<br \/>\n<\/em><\/p>\n<\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/section>\n","protected":false},"excerpt":{"rendered":"Apr\u00e8s avoir d\u00e9montr\u00e9 que ce quadrilat\u00e8re est un trap\u00e8ze, d\u00e9termine son aire. Solution1. Pente de JK 3\/4 2. Pente de GH 3\/4 Le quadrilat\u00e8re est un trap\u00e8ze! 3. R\u00e8gle de la droite JK y = 3\/4 x + 1,5 4. Pente de la droite perpendiculaire \u00e0 JK passant par G -4\/3 5. R\u00e8gle de la...","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-983","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/pascal-tic.org\/math\/wp-json\/wp\/v2\/pages\/983","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pascal-tic.org\/math\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/pascal-tic.org\/math\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/pascal-tic.org\/math\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/pascal-tic.org\/math\/wp-json\/wp\/v2\/comments?post=983"}],"version-history":[{"count":11,"href":"https:\/\/pascal-tic.org\/math\/wp-json\/wp\/v2\/pages\/983\/revisions"}],"predecessor-version":[{"id":2027,"href":"https:\/\/pascal-tic.org\/math\/wp-json\/wp\/v2\/pages\/983\/revisions\/2027"}],"wp:attachment":[{"href":"https:\/\/pascal-tic.org\/math\/wp-json\/wp\/v2\/media?parent=983"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}